n^2-35n-342=0

Solution for n^2-35n-342=0 equation:

n^2-35n-342=0

a = 1; b = -35; c = -342;
Δ = b2-4ac
Δ = -352-4·1·(-342)
Δ = 2593
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{2593}}{2*1}=\frac{35-\sqrt{2593}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{2593}}{2*1}=\frac{35+\sqrt{2593}}{2}
$